If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ≥ 1, then x20 – x19 =
A.2^19
B.2^20
C.2^21
D.2^20 - 1
E.2^21 - 1
Ans: A
這題我解到最後變成是 2^19-2^18接下來如何化簡成答案A 2^19呢???
[問題]GWD-13-30
版主: shpassion, Traver0818
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[問題]GWD-13-30
由 Grace » 2004-12-11 10:06
Q30:
If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ≥ 1, then x20 – x19 =
A.2^19
B.2^20
C.2^21
D.2^20 - 1
E.2^21 - 1
Ans: A
這題我解到最後變成是 2^19-2^18接下來如何化簡成答案A 2^19呢???
If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ≥ 1, then x20 – x19 =
A.2^19
B.2^20
C.2^21
D.2^20 - 1
E.2^21 - 1
Ans: A
這題我解到最後變成是 2^19-2^18接下來如何化簡成答案A 2^19呢???
- Grace
- 中級會員
- 文章: 171
- 註冊時間: 2004-08-25 21:42
- 來自: Kaohsiung
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