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文章weirdude » 2007-04-27 19:46

please help.
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文章vantreal » 2007-04-28 01:05

to know whether 0 is halfway between r and s
--> need to know whether l 0-r l = l s-0 l and r <0, s >0, which means r = -s, or s = -r

(1) s > 0
--> insufficient, s can be any number, it does not give me any relationship between r and s.

(2) l t - r l = l t - (-s) l
--> insufficient, we are not sure where 0 is, so we can not determine whether s is positive.

(1) + (2)
when s > 0, 0 is on the left hand side of s.
so l t - r l = t - r and l t - (-s) l = t +s,
t - r = t + s,
get rid of t,
now you can determine whether -r = s

Answer: (C)
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文章weirdude » 2007-05-12 22:36

got it!
thank you very much!
weirdude
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P1-DS-Q190

文章Philosophia » 2008-07-01 21:31

還是想不透 (2)

因為 on the number line shown, t>s>r
所以若l t - r l = l t - (-s) l
when t<0 --> s<0, r<0, and s=r ==>impossible: t>s>r
when t=0 --> s<0, r<0, and s=r ==>impossible: t>s>r
when t>0 --> if s>0 and r>0 --> s=r ==>impossible: t>s>r
         if s<0 and r<0 --> s=r ==> impossible: t>s>r
         if s>0 and r<0 --> s=-r ==>zero is halfway between r and s

還是想不透為什麼答案是 C
因為在t>s>r的條件下,要滿足(2),0 就會分別在 r 與 s 之間了,不是嗎?
Philosophia
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P1-DS-Q190

文章Philosophia » 2008-07-02 21:53

Philosophia \$m[1]:還是想不透 (2)

因為 on the number line shown, t>s>r
所以若l t - r l = l t - (-s) l
when t<0 --> s<0, r<0, and s=r ==>impossible: t>s>r
when t=0 --> s<0, r<0, and s=r ==>impossible: t>s>r
when t>0 --> if s>0 and r>0 --> s=r ==>impossible: t>s>r
         if s<0 and r<0 --> s=r ==> impossible: t>s>r
         if s>0 and r<0 --> s=-r ==>zero is halfway between r and s

還是想不透為什麼答案是 C
因為在t>s>r的條件下,要滿足(2),0 就會分別在 r 與 s 之間了,不是嗎?


請問有人可以幫我嗎?或是因為這篇舊文的標題下得不精確,大家都沒看到呢?... ;''(
Philosophia
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文章: 235
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P1-DS-Q190

文章Philosophia » 2008-07-03 15:23

可能是因為大家無法下載圖形,無法看到題目,所以我重新開版發問

附上連結http://www.chemy.idv.tw/phpbb2/viewtopic.php?t=29998
Philosophia
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