[問題]GWD21-Q10

[hccill]

不好意思,實在是搜不到文,所以又來波了~

Q10
If d=1/(2^3*5^7) is expressed as a terminating decimal. how many nonzero digits will d have?

(A).One
(B).Two
(C).Three
(D).Seven
(E).Ten

答案是B

請問除了乘開再除之外,還有什麼好方法嗎??

感恩喔~

[FrankChang]

d=1/(2^3*5^7)=2^4/10^7=16*0.0000001

[hccill]

好方法~
妙耶~
謝啦!

[ilovecushi]

d=1/(2^3*5^7)=2^4/10^7=16*0.0000001

why is it so?

thanks

[Huang Hsin-Yi]

d=1/(2^3*5^7)=2^4/2^7*5^7=2^4/10^7