Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112

Deprecated: preg_replace(): The /e modifier is deprecated, use preg_replace_callback instead in /home/formosam/public_html/phpBB3/includes/bbcode.php on line 112
FormosaMBA 傷心咖啡店 • 檢視主題 - [問題]GWD GMAT2 #22

[問題]GWD GMAT2 #22

關於 Problem Solving 和 Data Sufficiency 的問題都可以在這邊發表

版主: shpassion, Traver0818

[問題]GWD GMAT2 #22

文章sabrina » 2004-12-29 20:23

A consstruction company was paid a total of $500000 for a construction project.The company's only costs for the project were for labor and materials.Was the company's profit for the project greater than $150000?

(1) The company's total cost was three times its cost fir materials
(2) The company's profit was greater than its cost for labor.


ANS : C

Does anyone know how to solve this question?
sabrina
初級會員
初級會員
 
文章: 29
註冊時間: 2004-10-28 20:00

文章pcl12 » 2004-12-29 22:09

這題我本來也不懂,後來有上CD去看一些帖子..
我的方法看起來不怎麼高明,你加減參考一下吧..
只從(1)是得不到答案的,因為它只能得出
令T=3x, M=x 而T=L+M=500,000, M=500,000/3(約166,666)
但(1)根本沒提profit,無法判斷
(2)沒有給數據,只給他們的關係,無法判斷
(1)+(2)
profit>L=333,334,(利用(1)-->500,000-166,666),profit>333,334>150,000
頭像
pcl12
中級會員
中級會員
 
文章: 103
註冊時間: 2004-12-03 19:26

Re: [問題]GWD GMAT2 #22

文章 » 2004-12-29 22:18

sabrina \$m[1]:A consstruction company was paid a total of $500000 for a construction project.The company's only costs for the project were for labor and materials.Was the company's profit for the project greater than $150,000?

(1) The company's total cost was three times its cost for materials
(2) The company's profit was greater than its cost for labor.


ANS : C

Does anyone know how to solve this question?


應該是題目看不懂吧?

公司的支出labor and material合計共$500,000 , 問根據此合約的獲利是否有大於 $150,000
(1) L+M =$500,000 =3M.....可得M/L各為多少 ,無法得知(獲利)P
(2) P > L

(1) + (2) , 可得知L 為多少 即可得知 P > or < $150,000
白金會員
白金會員
 
文章: 2290
註冊時間: 2004-08-24 19:24

文章sabrina » 2004-12-29 22:20

but...$500000 is the amount that the company was paid instead of the cost..
sabrina
初級會員
初級會員
 
文章: 29
註冊時間: 2004-10-28 20:00

文章pcl12 » 2004-12-29 22:29

喔喔...
我懂你的意思....
看得好細,你是說500,000可能只是預付款之類的吧..而不是真正的成本..
是這個意思吧
頭像
pcl12
中級會員
中級會員
 
文章: 103
註冊時間: 2004-12-03 19:26

文章 » 2004-12-29 23:00

pcl12 \$m[1]:喔喔...
我懂你的意思....
看得好細,你是說500,000可能只是預付款之類的吧..而不是真正的成本..
是這個意思吧


挖 隊噎 有可能 媽呀 不會考這麼麻煩吧 @@
白金會員
白金會員
 
文章: 2290
註冊時間: 2004-08-24 19:24

Re: [問題]GWD GMAT2 #22

文章sharonstone » 2004-12-29 23:04

sabrina \$m[1]:A consstruction company was paid a total of $500000 for a construction project.The company's only costs for the project were for labor and materials.Was the company's profit for the project greater than $150000?

(1) The company's total cost was three times its cost fir materials
(2) The company's profit was greater than its cost for labor.


ANS : C

Does anyone know how to solve this question?


我的想法不知道對不對
大家來看看

首先我設material為X,labor為Y (why?因為我個人喜歡:P)
所以根據題目所說的
profit=500000-(X+Y)有沒有>150000
從(1)可知3X=X+Y
從(2)可知500000-(X+Y)>Y

化簡上述式子
其實就是要問在2X=Y且X+2Y<500000之下
X+Y有沒有 <350000
畫一下圖就會發現
還真的有咧... :|||
Do~ Do Si Do Si So~
La Mi~ Mi So La Re~
Si Do~ Do Si Do Re.Si.So~ Do Si La_ Do Si La_ Do Si La .......
http://www.wretch.cc/blog/sharonstone
頭像
sharonstone
黃金會員
黃金會員
 
文章: 811
註冊時間: 2004-11-21 15:28


回到 GMAT MATH 考區

誰在線上

正在瀏覽這個版面的使用者:沒有註冊會員 和 6 位訪客